C# Convert the Object to a JSON String

  1. C# Program to Convert an Object to JSON String Using JavaScriptSerializer().Serialize() Method
  2. C# Program to Convert an Object to a JSON String Using JsonConvert.SerializeObject() Method
  3. C# Program to Convert an Object to JSON String Using JObject.FromObject() Method

In C#, information can be converted into a useful format called JavaScript Object Notation (JSON). It is converted because the JSON format is simpler to understand and easier to process.

This article focuses on the methods to convert a C# object into a JSON string.

C# Program to Convert an Object to JSON String Using JavaScriptSerializer().Serialize() Method

To implement this method, we first create a custom class object that contains the information. This object is then passed as a parameter to JavaScriptSerializer().Serialize() method. As a result, we get our information converted to a JSON string.

The correct syntax to use this method is as follows:

var jsonStringName = new JavaScriptSerializer();
var jsonStringResult = jsonStringName.Serialize(ObjectName);

Example Code:

using System;
using System.Web.Script.Serialization;


class Conversion
{
    static void Main()
    {
        //Creating Custom Class Object
        var Object = new MyInformation
        {
            firstName = "Olivia",
            lastName = "Mason",
            dateOfBirth = new DateOfBirth
            {
                year = 1999,
                month = 06,
                day = 19
            }
        };
        //Creating a JavaScriptSerializer Object
        var jsonString = new JavaScriptSerializer();
        //Use of Serialize() method
        var jsonStringResult = jsonString.Serialize(Object);
        Console.WriteLine(jsonStringResult);
    }
}
//Custom Classes
public class MyInformation
{
    public string firstName;
    public string lastName;
    public DateOfBirth dateOfBirth;
}

public class DateOfBirth
{
    public int year;
    public int month;
    public int day;
    
}

Output:

{
    "firstName":"Olivia",
    "lastName":"Mason",
    "dateOfBirth":
    {
        "year":"1999",
        "month":"06",
        "day":"19"
    }
}

C# Program to Convert an Object to a JSON String Using JsonConvert.SerializeObject() Method

JsonConvert.SerializeObject() is a JsonConvert class method. It is used to convert a C# object into a JSON string. The object is passed as a parameter to this method.

The correct syntax to use this method is as follows:

JsonConvert.SerializeObject(ObjectName);

Example Code:

using System;
using Newtonsoft.Json;
 
 
namespace JSONConversion
{
    public class Conversion
    {
        public static void Main(string[] args)
        {
            //Creating custom class object
            Name NewName =new Name
                 {FirstName = "Olivia",
                  LastName = "Mason"};
            //Use of JsonConvert.SerializeObject()
            string jsonString = JsonConvert.SerializeObject(NewName);
            Console.WriteLine(jsonString);
}  
        //Creating custom class
public class Name  
{  
    public string FirstName;  
    public string LastName;    
 
}
    }
}

Output:

{
    'FirstName': 'Olivia',
    'LastName': 'Mason'
}

C# Program to Convert an Object to JSON String Using JObject.FromObject() Method

This method can be implemented in the earlier versions of .Net. It easily converts a C# object to a JSON string. The object name is passed as a parameter to this method.

The correct syntax to use this method is as follows:

JObject.FromObject(ObjectName);

Example Code:

using System;
using Newtonsoft.Json.Linq;

 
namespace JSONConversion
{
    public class Conversion
    {
        public static void Main(string[] args)
        {
             name Name = new name 
             {firstname = "Olivia",
             lastname = "Mason"};
             //Use of the method
             var json = JObject.FromObject(Name);  
             Console.WriteLine(json); 
         }  
public class name{
    public string firstname;
    public string lastname;
       }
    }
}
    

Output:

{
  "firstname": "Olivia",
  "lastname": "Mason"
}

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