# Use of 128-Bit Integer in C++

In this tutorial, we will discuss 128-bit integers in C++. We will also see why we need it and the possible alternatives in C++.

## Use of 128-Bit Integer in C++

We have multiple choices to handle integers in C++. Starting from `int` data type to `long`, `long int`, and `long long int` that has 64-bits and the maximum positive number that we can store is `9223372036854775807` (in hexadecimal `7FFFFFFFFFFFFFFF`).

Consider `7` in hexadecimal number; next, we will have `8`, having binary `1000`, which means the sign bit is on. Finally, we have negative integers from `-1` to `-9223372036854775808`.`9223372036854775807` is a number big enough to handle many storage plus arithmetic operations requirements.

### Importance of 128-Bit Integer & Its Alternatives in C++

Now, if you need even bigger integers, the question is, do we want to perform arithmetic operations on those integers? If the answer is yes, you might probably need more storage than 128-bits.

The result of the addition or multiplication of two big integers might need more bits. Therefore, in this case, implementing big integers might help you.

Lastly, if you need a 128-bit integer for storage only, one solution is to create a structure of two 64-bit integers, or you might take an `int` array of `8` elements or a `char` array of `16` elements.

However, GCC does provide a specific data type for 128-bit integers that is `int128_t`; on supported compilers, you can check the size:

``````int128_t var;
cout << sizeof(var) << '\n';
``````

The output will be `16`, which means `16x8=128 bits`.

However, it is supported for specific processors, which are capable of holding 128-bits; otherwise, when you try to store a big integer, the compiler generates one of the following warnings:

`````` warning: overflow in implicit constant conversion
warning: integer constant is too large for its type
``````

The conclusion of the discussion is to decide precisely how many bits will be required in the worst case.

Further, do you want to store data only, or do you want to perform arithmetic operations? Then, Big Integer implementation is your solution if you want to perform arithmetic operations.

In the case of Big Integer implementation, you don’t have to worry about even 500 or 5000 bits.

If you want to do storage only, you have other solutions available. Use structure of two, 64-bits data members, or use array of `int` data type or `char` data type.

## Related Article - C++ Integer

• Big Integer in C++
• Specify 64-Bit Integer in C++
• Comparison Between Signed and Unsigned Integer Expressions in C++