# Return Boolean With If-Else in Scala

This article will teach us how to return Boolean values when working with `if-else` in Scala.

## Return Boolean With `if-else` in Scala

Let’s see a scenario to understand it better.

``````def check(): Boolean = {
for ((digit1,digit2,digit3) <- digitsSet){
if ((1,5,6) == (digit1,digit2,digit3))
true
else
false
}
}

val digitsSet = Set((10,20,30),(1,5,6),(78,109,23),(14,25,57))
``````

In the above code, we are trying to find whether our set contains those three digits, so we expect either `true` or `false` as the output, but when the above code is executed, we get the following error.

``````type mismatch;
found   : Unit
required: Boolean
for ((digit1,digit2,digit3) <- digitsSet){
``````

The problem is that the function should return Boolean instead of `Unit`.

So we can solve this problem in different ways.

1. Using the `contains` method to find an element in our set. It returns `true` if the element is present; else returns `false`.

This is a more elegant way of writing the above code.

Example code:

``````val digitsSet = Set((10,20,30),(1,5,6),(78,109,23),(14,25,57))
println(digitsSet.contains((10,20,30)))
``````

Output:

``````true
``````
2. Adding a `return` statement before `true` and `false`. This is the best way as it is versatile and can be used in almost any scenario.

`````````scala
val digitsSet = Set((10,20,30),(1,5,6),(78,109,23),(14,25,57))

def check(): Boolean = {
val store = for ((digit1,digit2,digit3) <- digitsSet) {
if ((10,20,30) == (digit1,digit2,digit3))
return true
}
false
}

println(check())
```

Output:

```text
true
```
``````
1. Using the `exists` method in Scala.

``````val digitsSet = Set((10,20,30),(1,5,6),(78,109,23),(14,25,57))

println(digitsSet.exists( _ == (1,20,50) ))
``````

Output:

``````false
``````
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